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1/6+1/12+1/20+…+1/72+1/90+1/110=

1/2+1/6+1/12+1/20+1/30+1/42+1/56+1/72+1/90 =1/(1*2

解: 如上图所示

原式拆分,连续抵消,结果是1/3-1/11=8/33

1/12+1/20+1/30+1/42+1/56+1/72+1/90 =(1/3-1/4)+(1/4

如图

1/2+5/6+11/12+19/20+29/30+41/42+55/56+71/72+89/90+

1/2+1/6+1/12+1/20+1/30+1/42+1/56 =1/2+(1/6+1/12)+(

解: 原式 =(1+3+5+……+19)+(1/6+1/12+1/20+……+1/110) =(1+

把1去掉,直接把其他数相加,2+6+12+20……

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