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25×37+34×28用简便运算怎么算

22+25+28+31+34+37 =(22+28)+【25+(31+34)】+37 =50+【25+65】+37 =50+90+37 =140+37 =177

37×34+37×28+38×37 =37x(34+28+38) =37x100 =3700

125*34*8*37 =125*8*34*37 =1000*34*37 =1000*(30+4)*(30+7) =1000*(30*30+30*7+4*30+4*7) =1000*(900+210+120+28) =1000*1258 =1258000

解;33×34+34×35+35×36+36×37+37×38,=33×(35-1)+34×35+35×36+(35+1)×37+(35+2)×38,=33×35-33+34×35+35×36+35×37+37+35×38+2×38,=35×(33+34+36+37+38)-33+37+76,=35×(200-22)+80,=7000-770+80,=6310.

(1)25×125×4,=(25×4)×125,=100×125,=12500;(2)38×101,=38×(100+1),=38×100+38×1,=3800+38,=3838;(3)27×[(263+37)÷50],=27×[300÷50],=27×6,=162;(4)34×72+34×28,=34×(72+28),=34×100,=3400.

吧相邻两项放在一起,相当于10个1相加

解 7+10+13+16+19+22+25+28+31+34+37 =(7+37)÷2×11 =22×11 =242

原式 =(1+49)+(4+46)+……+(22+28)+25 =50+50+……+50+25 =50x8+25 =400+25 =425

先求25+28+31+34+37+40+43……+91+94+97里有多少个数, 连续的两数差是3, 再用头尾相加的和乘以个数除以2 ,则 数的个数是: (97 - 25)÷(28 - 25)+1 =72÷3+1 =24+1 =25(个) 总和是: (25+97)×25÷2 =122×25÷2 =3050÷2 =1525

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