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python 从txt中读取数据到 list 中

python3.x result=[] with open('a.txt','r') as f: for line in f: result.append(list(map(float,line.split(',')))) print(result) python2.7 result=[] with open('a.txt','r') as f: for line in f: result.append(map(float,line.split(',...

背景: 文件内容每一行是由N个单一数字组成的,每个数字之间由制表符区分,比如: 0 4 3 1 2 2 1 0 3 1 2 0 …… 现在需要将每一行数据存为一个list,然后所有行组成一个大的list。 工具: 1.strip():用于移除字符串头尾指定的字符,默认为空格,...

#!/usr/bin/pythonf = open('myfile.txt','r')lines = f.readlines()names = locals()for line in lines: index = int(lines.index(line))+1 names['list%d' % index] = line.split()print "list1 = " + str(list1)print "list2 = " + str(list2...

filename = r'a.txt'alist = []lines = open(filename,'r').readlines()alist = [line.strip().split(',')[3] for line in lines ]#字段以逗号分隔,这里取得是第4列

python读取文件内容的方法: 一.最方便的方法是一次性读取文件中的所有内容并放置到一个大字符串中: all_the_text = open('thefile.txt').read( ) # 文本文件中的所有文本 all_the_data = open('abinfile','rb').read( ) # 二进制文件中的所有...

#!/usr/bin/env python3.6import refname = 'a.txt'with open(fname) as f: s = f.read()numbers = [int(i) for i in re.findall(r'\d+', s)]print(f'numbers: {numbers}\nsum: {sum(numbers)}')

array = []for line in open('testdata.txt'): array.extend(line.strip().split(' '))array = map(int, array)print(array)

so easy import rewith open('lists.txt') as f: s = f.read()alltogether = sum(int(i) for i in re.findall(r'\d+', s))

data = []for l in open("a.txt"): row = [int(x) for x in l.split()] if len(row) > 0: data.append(row)

def itemfactory(filename, parserfunc): """用给定的加工方法对文件中的每一行进行处理""" with open(filename, 'rt') as handle: for ln in handle: yield parserfunc(ln)for a, b in itemfactory( "data.txt", # 加工方法是将行字符串拆分后...

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