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python 从txt中读取数据到 list 中

python3.x result=[] with open('a.txt','r') as f: for line in f: result.append(list(map(float,line.split(',')))) print(result) python2.7 result=[] with open('a.txt','r') as f: for line in f: result.append(map(float,line.split(',...

#!/usr/bin/pythonf = open('myfile.txt','r')lines = f.readlines()names = locals()for line in lines: index = int(lines.index(line))+1 names['list%d' % index] = line.split()print "list1 = " + str(list1)print "list2 = " + str(list2...

背景: 文件内容每一行是由N个单一数字组成的,每个数字之间由制表符区分,比如: 0 4 3 1 2 2 1 0 3 1 2 0 …… 现在需要将每一行数据存为一个list,然后所有行组成一个大的list。 工具: 1.strip():用于移除字符串头尾指定的字符,默认为空格,...

##文件中内容cat a.txt (('aa', 6L), [('n', '3CE'), ('c', '48'), ('c', 'ff')])(('bb', 5L), [('n', '4E5'), ('c', '28'), ('c', '2'), ('c', '8')])(('cc', 2L), [('n', '5DC'), ('c', '108'), ('c', '4'), ('c', '2'), ('c', '4')])#python...

#Python3 fp=open("a.txt",“r”) arr=[] for lines in fp.readlines(): lines=lines.replace("\n","").split(",") arr.append(lines) print(arr) fp.close()

so easy import rewith open('lists.txt') as f: s = f.read()alltogether = sum(int(i) for i in re.findall(r'\d+', s))

# coding: UTF-8blist = []split_char = ' 'with open('b.txt', 'r') as bf: blist = [b.strip().split(split_char) for b in bf]word = '我'print repr(word)for bl in blist: print bl if word in bl: print 'blist[%d][%d]' % (blist.index(b...

#!/usr/bin/env python3.6import refname = 'a.txt'with open(fname) as f: s = f.read()numbers = [int(i) for i in re.findall(r'\d+', s)]print(f'numbers: {numbers}\nsum: {sum(numbers)}')

解决方案如下: import osfp=open(r"C:\Users\YYC\Desktop\aa.txt")result=[]for linea in fp.readlines(): linea=linea.split(" ")[:-1] result.append(linea)fp.close()print result打开文件进行读操作,用open; 生命一个数组用来存放数据; ...

array = []for line in open('testdata.txt'): array.extend(line.strip().split(' '))array = map(int, array)print(array)

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