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python编程关于数字位数与数字比较问题

a = 1234 b = 3456 a1 =str(a) b1 = str(b) n = 0 for i in a1: for j in b1: if i == j: n += 1 print n,"digits are same"

a=int(input())n=0while(a>=1): a//=10 n+=1print(n)

f = lambda x, n: round(x, n - len(str(int(x)))); 定义了一个方法f,用来实现你所说的功能。 输入: f(123.456789, 8) 输出: 123.45678 输入: f(1.23456789, 8) 输出: 1.2345679000000001 f接收2个参数,第一个参数是要求有效位数的数字,...

for i in range(1,5): for j in range(1,5): for n in range(1,5): for k in range(1,5): if k != n and k != j and k!= i and n!= j and n!=i and j!=i: print (i,j,n,k)

s = input() #输入print(s[::-1]) #反序输出print(len(s)) #输出位数

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list = [2,4,5,9,] i=0 m=0 n=0 if i

import randomdef gen3num(): alldigit=[0,1,2,3,4,5,6,7,8,9] first=random.randint(1,9) alldigit.remove(first) second=random.choice(alldigit) alldigit.remove(second) third=random.choice(alldigit) return first*100+second*10+thirdif...

for i in range(1,10001): print(i) with open('txt.txt', 'a') as fw: fw.write(str(i) + '\n')

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